Seeing G as a default force for when the m1m2/r^2 ratio =1

 If we see G as the default force for when the dimensionless ratio  of m1m2/r^2 is 1.  

So in this view G just has the extra units to make m1m2/r^2  a dimensionless ratio.  Otherwise G would just be a simple force formula.  

If we align the Force we are talking about with the velocity in the F=ma formula we can see that  G = m a  becomes a default mass times velocity per second. 

G = 2.79765968600242198374066111203-18 kg * 299792458 m/s²

And then the units in m1m2/r^2 are stripped away by the extra units addeded to the default F=ma formula we called G.  This means that m1m2/r^2 becomes dimensionless.  It is just a ratio.

if m1 = m2 = 1Kg at a meter radius that ratio is 1 and the force formula that is hardcoded in G is just taken as is, the units being converted into units of force.  

If you doubled the masses to 2Kg or you halved the distance then the ratio becomes 4 instead of 1 and you get 4 times that default force formula.  If you went to two 1/2 kg masses or made the distance 2 meters, then the force would be 1/4th the default value.  

And you can look at these masses as frequencies by just converting them all to frequencies by dividing the mass by Q_m kg s, the conversion factor for mass and frequency. 

Q_m = h/c^2 = 7.372497323812708e-51 kg s

F = G m1m2/r^2 becomes

F = m_d * c * m1*m2 /r^2

F/ Q_m^3  = m_d / Q_m * c * ((m1 /Q_m) * (m2 / Q_m)) / r^2

F/ Q_m^3  = m_d / Q_m * c * ((m1 /Q_m) * (m2 / Q_m)) / r^2

F/ Q_m^3  = f_d * c * f1 * f2 / (r^2 * Q_m^3)

F = f_d * c* f1 * f2 /r^2

And if we went to natural units where c =1 for the radius squared, (r/c)^2 for fraction of the length in light seconds then the radius is a fraction.  

F = f_d * f1 * f2 /(r/c)^2  where c is the current value for c, and r was the former meters, but this is now a light second distance as a fraction.  I think this changes the F value by the former value of c. 

You can see that just using the frequencies we get the same results.