Mastodon Politics, Power, and Science: The simple version of Hawking temp of a blackhole.

Sunday, June 8, 2025

The simple version of Hawking temp of a blackhole.

you have an idea about black hole temp and you think it has something to do with T = 1/M with some geometry

Well you can just make that dimensionless,

T_H /T_P= m_P * / (16pi^2 M)

solve for SI temp
T_H = m_P * T_P / (16pi^2 M)

decompose to the fundamental jacobeans and simplify
T_H = (Hz_kg / t_P) * ( 1/ K_Hz t_P )/(16 pi^2 (f_H * Hz_kg)
T_H = 1/(16 pi^2 (f_H * t_P^2 * K_Hz )
T_H = 1/(16 pi^2 * t_P^2 * f_H) * Hz_K *
T_H = 1/(16 pi^2 * t_P * mass in plack units) * Hz_K

And that is the answer at the planck scale getting scale back to si units of temp

Then you can just keep going and find the answer in normal si math

f_H = 1 / (16 * π² * t_P^2 * f_C )
= c³ / (16 * π² * ( t_P^2 * c^3 / H_kg) * f_C * Hz_kg )
= c³ / (16 * π² * G * M)
Hz_K = h/k_B
T_H = f_H * Hz_K

And there is the standard hawking temp.

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